3.25.24 \(\int (a+b (c x^n)^{2/n})^3 \, dx\)

Optimal. Leaf size=62 \[ a^3 x+a^2 b x \left (c x^n\right )^{2/n}+\frac {3}{5} a b^2 x \left (c x^n\right )^{4/n}+\frac {1}{7} b^3 x \left (c x^n\right )^{6/n} \]

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Rubi [A]  time = 0.02, antiderivative size = 62, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {254, 194} \begin {gather*} a^2 b x \left (c x^n\right )^{2/n}+a^3 x+\frac {3}{5} a b^2 x \left (c x^n\right )^{4/n}+\frac {1}{7} b^3 x \left (c x^n\right )^{6/n} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*(c*x^n)^(2/n))^3,x]

[Out]

a^3*x + a^2*b*x*(c*x^n)^(2/n) + (3*a*b^2*x*(c*x^n)^(4/n))/5 + (b^3*x*(c*x^n)^(6/n))/7

Rule 194

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[ExpandIntegrand[(a + b*x^n)^p, x], x] /; FreeQ[{a, b}, x]
&& IGtQ[n, 0] && IGtQ[p, 0]

Rule 254

Int[((a_) + (b_.)*((c_.)*(x_)^(q_.))^(n_))^(p_.), x_Symbol] :> Dist[x/(c*x^q)^(1/q), Subst[Int[(a + b*x^(n*q))
^p, x], x, (c*x^q)^(1/q)], x] /; FreeQ[{a, b, c, n, p, q}, x] && IntegerQ[n*q] && NeQ[x, (c*x^q)^(1/q)]

Rubi steps

\begin {align*} \int \left (a+b \left (c x^n\right )^{2/n}\right )^3 \, dx &=\left (x \left (c x^n\right )^{-1/n}\right ) \operatorname {Subst}\left (\int \left (a+b x^2\right )^3 \, dx,x,\left (c x^n\right )^{\frac {1}{n}}\right )\\ &=\left (x \left (c x^n\right )^{-1/n}\right ) \operatorname {Subst}\left (\int \left (a^3+3 a^2 b x^2+3 a b^2 x^4+b^3 x^6\right ) \, dx,x,\left (c x^n\right )^{\frac {1}{n}}\right )\\ &=a^3 x+a^2 b x \left (c x^n\right )^{2/n}+\frac {3}{5} a b^2 x \left (c x^n\right )^{4/n}+\frac {1}{7} b^3 x \left (c x^n\right )^{6/n}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 62, normalized size = 1.00 \begin {gather*} a^3 x+a^2 b x \left (c x^n\right )^{2/n}+\frac {3}{5} a b^2 x \left (c x^n\right )^{4/n}+\frac {1}{7} b^3 x \left (c x^n\right )^{6/n} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*(c*x^n)^(2/n))^3,x]

[Out]

a^3*x + a^2*b*x*(c*x^n)^(2/n) + (3*a*b^2*x*(c*x^n)^(4/n))/5 + (b^3*x*(c*x^n)^(6/n))/7

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IntegrateAlgebraic [F]  time = 0.54, size = 0, normalized size = 0.00 \begin {gather*} \int \left (a+b \left (c x^n\right )^{2/n}\right )^3 \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(a + b*(c*x^n)^(2/n))^3,x]

[Out]

a^3*x + Defer[IntegrateAlgebraic][b*(c*x^n)^(2/n)*(3*a^2 + 3*a*b*(c*x^n)^(2/n) + b^2*(c*x^n)^(4/n)), x]

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fricas [A]  time = 1.26, size = 52, normalized size = 0.84 \begin {gather*} \frac {1}{7} \, b^{3} c^{\frac {6}{n}} x^{7} + \frac {3}{5} \, a b^{2} c^{\frac {4}{n}} x^{5} + a^{2} b c^{\frac {2}{n}} x^{3} + a^{3} x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(c*x^n)^(2/n))^3,x, algorithm="fricas")

[Out]

1/7*b^3*c^(6/n)*x^7 + 3/5*a*b^2*c^(4/n)*x^5 + a^2*b*c^(2/n)*x^3 + a^3*x

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giac [A]  time = 0.20, size = 52, normalized size = 0.84 \begin {gather*} \frac {1}{7} \, b^{3} c^{\frac {6}{n}} x^{7} + \frac {3}{5} \, a b^{2} c^{\frac {4}{n}} x^{5} + a^{2} b c^{\frac {2}{n}} x^{3} + a^{3} x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(c*x^n)^(2/n))^3,x, algorithm="giac")

[Out]

1/7*b^3*c^(6/n)*x^7 + 3/5*a*b^2*c^(4/n)*x^5 + a^2*b*c^(2/n)*x^3 + a^3*x

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maple [F]  time = 0.33, size = 0, normalized size = 0.00 \begin {gather*} \int \left (b \left (c \,x^{n}\right )^{\frac {2}{n}}+a \right )^{3}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*(c*x^n)^(2/n))^3,x)

[Out]

int((a+b*(c*x^n)^(2/n))^3,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} b^{3} c^{\frac {6}{n}} \int {\left (x^{n}\right )}^{\frac {6}{n}}\,{d x} + 3 \, a b^{2} c^{\frac {4}{n}} \int {\left (x^{n}\right )}^{\frac {4}{n}}\,{d x} + 3 \, a^{2} b c^{\frac {2}{n}} \int {\left (x^{n}\right )}^{\frac {2}{n}}\,{d x} + a^{3} x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(c*x^n)^(2/n))^3,x, algorithm="maxima")

[Out]

b^3*c^(6/n)*integrate((x^n)^(6/n), x) + 3*a*b^2*c^(4/n)*integrate((x^n)^(4/n), x) + 3*a^2*b*c^(2/n)*integrate(
(x^n)^(2/n), x) + a^3*x

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mupad [B]  time = 1.25, size = 58, normalized size = 0.94 \begin {gather*} a^3\,x+\frac {b^3\,x\,{\left (c\,x^n\right )}^{6/n}}{7}+a^2\,b\,x\,{\left (c\,x^n\right )}^{2/n}+\frac {3\,a\,b^2\,x\,{\left (c\,x^n\right )}^{4/n}}{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*(c*x^n)^(2/n))^3,x)

[Out]

a^3*x + (b^3*x*(c*x^n)^(6/n))/7 + a^2*b*x*(c*x^n)^(2/n) + (3*a*b^2*x*(c*x^n)^(4/n))/5

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sympy [A]  time = 0.99, size = 63, normalized size = 1.02 \begin {gather*} a^{3} x + a^{2} b c^{\frac {2}{n}} x \left (x^{n}\right )^{\frac {2}{n}} + \frac {3 a b^{2} c^{\frac {4}{n}} x \left (x^{n}\right )^{\frac {4}{n}}}{5} + \frac {b^{3} c^{\frac {6}{n}} x \left (x^{n}\right )^{\frac {6}{n}}}{7} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(c*x**n)**(2/n))**3,x)

[Out]

a**3*x + a**2*b*c**(2/n)*x*(x**n)**(2/n) + 3*a*b**2*c**(4/n)*x*(x**n)**(4/n)/5 + b**3*c**(6/n)*x*(x**n)**(6/n)
/7

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